Betty Boop

Here is another version of the code which I have been using and this does the same output as the one underneath it.

<form action='trial.php' method='GET'>

<input type="text" name="search_term"/>
<input type="submit" value="Find"/>

</form>

<?php
// the if statement if there is nothing in the search box
if(empty($_GET['search_term']))
{
print "This must not be left blank!";
exit(0);
}
$search = $_GET['search_term'];

//Url for imdb
$url = file_get_contents("http://www.deanclatworthy.com/imdb/?q=".urlencode($search));
$data =($url);

print $data;

2nd Version:



<form action='trial.php' method='GET'>

<input type="text" name="search_term"/>
<input type="submit" value="Find"/>

</form>

<?php
// the if statement if there is nothing in the search box
if(empty($_GET['search_term']))
{
print "This must not be left blank!";
exit(0);
}
$movie = $_GET['search_term'];

$movie = ("http://www.deanclatworthy.com/imdb/?q=");
$movie = explode(",". $movie);

$string = '{
"title":"",
"year":"",
"imdburl":"",
"country":"",
"languages":"",
"genres":"",
"rating":"",
"votes":"",
"usascreens":"",
"ukscreens":""
}';

$obj = json_decode($string);
printf('<a href="%s" title="%s">%s (%d)</a>', $obj->imdburl, $obj->title, $obj->title, $obj->year);

Any help would be much appreciated.

Betty Boop

I have just fiddled around with the code and at the moment it creates a link when the movie is searched and when you press the link it redirects you to the imdb web page!

I still need to add another api but at the moment it works. Thank you.

Betty Boop

Hi,

I just need to know exactly what this does:

$obj = json_decode($url);
printf('<a href="%s" title="%s">%s (%d)</a>', $obj->imdburl, $obj->title, $obj->title, $obj->year);

I know that it decodes the json into a php format. It does work which is great but if I want to add more details about the movie e.g. country I add that field as $obj->country after $obj->year and nothing appears?

davedevelopment

You will need to add another place holder in the first argument to the printf query. %s is the place holder for a string.

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Betty Boop

Thanks alot, I will try that now and then see what happens.

Betty Boop

Hi,

Does anyone know how to display the json output into a table?

I have tried some methods but it does not work.

Thanks alot everyone that has helped with the coding.

dtm

The following two links may help:

This is very basic and not very useful:
Creating and Parsing JSON data with PHP

If you can implement this class could be useful:
Table Constructor (html table) - PHP Classes

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Betty Boop

Hi,

Thanks a lot. Here is the code that I am working with:

$obj = json_decode($url);
printf('<a href="%s" title="%s">%s (%d) %s %s</a>', $obj->imdburl, $obj->title, $obj->title, $obj->year, $obj->country, $obj->genres);

I presume that I will need the

new Table ('data.json', 'json-file');

Betty Boop

Hi,

I have been trying to do this for ages now....here is the code I have got.

$obj = json_decode($url);

printf('%s (%d) %s %s %s', $obj->title, $obj->year, $obj->country, $obj->genres, $obj->rating);
printf('<a href="%s"> %s'</a>, $obj->imdburl);

I want to display the first printf without linking to the url, I want this information to be displayed in a table with html or php. With the 2nd printf I want a link called 'More Info' to take the user to the imdb page on the film that is searched.

Originally I had:

printf('<a href="%s" title="%s">%s (%d)</a>', $obj->imdburl, $obj->title, $obj->title, $obj->year);

This made the whole content hperlinked and when pressed it took the user to the imdb site with info about the film searched.

I probably haven't described it clearly but if anyone knows how to do this it would help a lot.

Thanks.

davedevelopment

This wont be exactly right, but should put you on track! No more help from me after this, you'll learn the most by finding your own way!

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