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Betty Boop · 12-01-2010, 01:05:57 PM

Hello,

I have this error now when I run my php code:

Notice: Trying to get property of non-object in C:\Program Files\EasyPHP5.3.0\www\New Folder\trial.php on line 39

Line 39 is: printf('<a href="%s" title="%s">%s (%d) %s %s</a>', $obj->imdburl, $obj->title, $obj->title, $obj->year, $obj->country, $obj->genres);

I read online that it maybe to do with the error reporting in the php.ini file and the default should be: Default Value: E_ALL & ~E_NOTICE

Mine is and it still has the error any ideas anyone?

nick279 · 12-01-2010, 01:13:54 PM

It means you are trying to access something that isn't there

e.g. a field, or part of the object

$obj->imdburl, $obj->title, $obj->title, $obj->year, $obj->country, $obj->genres

one, or all of the fields (items after ->) aren't properly setup

if you do a

Code:

die(print_r($obj));

on line 38 may help you see what is contained in $obj

Betty Boop · 12-01-2010, 02:04:29 PM

Hi,

Thanks that did show me what was is contained. It is correct so maybe it is something to do with Caching?

12-01-2010, 01:05:57 PM	#1 (permalink)
Betty Boop Junior Member Join Date: Jan 2010 Posts: 14 No Classified Ratings Domain Trader Rating: (0% / 0)	Notice: Trying to get property of non-object in Hello, I have this error now when I run my php code: Notice: Trying to get property of non-object in C:\Program Files\EasyPHP5.3.0\www\New Folder\trial.php on line 39 Line 39 is: printf('<a href="%s" title="%s">%s (%d) %s %s</a>', $obj->imdburl, $obj->title, $obj->title, $obj->year, $obj->country, $obj->genres); I read online that it maybe to do with the error reporting in the php.ini file and the default should be: Default Value: E_ALL & ~E_NOTICE Mine is and it still has the error any ideas anyone?

12-01-2010, 01:13:54 PM	#2 (permalink)
nick279 Join Date: Apr 2008 Posts: 653 No Classified Ratings Domain Trader Rating: (100% / 25)	It means you are trying to access something that isn't there e.g. a field, or part of the object $obj->imdburl, $obj->title, $obj->title, $obj->year, $obj->country, $obj->genres one, or all of the fields (items after ->) aren't properly setup if you do a Code: die(print_r($obj)); on line 38 may help you see what is contained in $obj

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12-01-2010, 02:04:29 PM	#3 (permalink)
Betty Boop Junior Member Join Date: Jan 2010 Posts: 14 No Classified Ratings Domain Trader Rating: (0% / 0)	Hi, Thanks that did show me what was is contained. It is correct so maybe it is something to do with Caching?